180=5(b)^2

Solution for 180=5(b)^2 equation:

180=5(b)^2

We move all terms to the left:

180-(5(b)^2)=0

determiningTheFunctionDomain
-5b^2+180=0

a = -5; b = 0; c = +180;
Δ = b2-4ac
Δ = 02-4·(-5)·180
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-5}=\frac{-60}{-10}
=+6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-5}=\frac{60}{-10}
=-6
$